Bonsoir
lim(x->0)[sin(pi Vcosx)]/x = lim(x->0)[-sin(pi(Vcosx - 1))]/x
= lim(x->0)[ (-sin(pi(Vcosx - 1)) / pi(Vcosx - 1) ) * pi(Vcosx - 1)/x ]
Nous avons: lim(x->0)[-sin(pi(Vcosx - 1)) / pi(Vcosx - 1)]=-1 (x-->0 => pi(Vcosx - 1)-->0 )
et : lim(x->0) [pi(Vcosx - 1)/x)] = lim(x->0) [((1-cosx)/x²) * -pi.x/(Vcosx + 1)]=0
alors :
lim(x->0)[sin(pi Vcosx)]/x=0
sauf erreur !!
''sorry for not using latex !!''