x>=1
si m=<0 ==> Rac(x-1)+Rac(x+1)-mRac(x)>0 qqs x >=1.
Si m>0
en élevant au carré ==> 2x+2Rac(x²-1)>m²x ==> 2Rac(x²-1)>(m²-2)x
Si m<Rac(2) ==> 2Rac(x²-1)>=0>(m²-2)x qqs x>=1
Si m>=Rac(2) , en élevant au carré ==> 4(x²-1)>(m²-2)²x² ==>m²(m²-4)x²+4<0
Si m>=2 pas de solution
Si m<2 , m²(m²-4)x²+4<0 <==> x² > 4/ (m²(4-m²)) <==> x> 2/ (m Rac(4-m²))
4 - m²(4-m²) =(m²-2)²>0 ==> 4>m²(4-m²) ==> 4/ (m²(4-m²)) >1 ==> 2/ (m Rac(4-m²))>1
Résumé :
Si m<Rac(2) , S=[1,+00[
Si m>=2 , S est vide
Si Rac(2)=<m<2 , S= ]2/ (m Rac(4-m²)),+00[
_________________
وقل ربي زد ني علما