exercice

li takon n mene N*wa x mene R. nada3:

m=-[n(r-1)] -1 et r=x-[x]

1-li takon k mene N bihayte: k<n

a- bayne ana : k≤ m =>[ r+k/n] =0

b- bayne ana : k> m =>[ r+k/n]=1

2- istantij ana :

[x ] + [x+(1/n)] +............+ [x+((n-1)/n)] =[ nx]