je note
epsilon=f
theta=t
sigma1=a et sigma2=b
w1=c et w2=d ==> c+d=1 et c,d>0
µ1=u et µ2=v ==> u>v
k=1/V2pi
f'(t)=- k (d/b) exp(-(t-u)²/2b²)+k(c/a) exp(-(t-v)²/2a²)=0
<==> exp(-(t-u)²/2b²+(t-v)²/2a²)= cb/ad
<==> -(t-u)²/2b²+(t-v)²/2a²= ln(cb/ad)
Equation de degré 2 en t ==> 2 racines ==> un minimum