ExerciceS

majdouline a écrit:

comment faire POUR CE F(x)?

voici comment factoriser F(x):

F(x)=x^8+x+1
F(x)=x^8+x+x²+1-x²
F(x)=(x^4-x)(x^4+x)+(x+1+x²)
F(x)=x²(x^3-1)(x^3+1)+(x+1+x²)
F(x)=x²(x-1)(x²+x+1)(x^3+1)+(x+1+x²)
F(x)=(x²+x+1)[x²(x-1)(x^3+1)+1]
F(x)=(x²+x+1)(x^6+x^3-x^5-x²+1)

c bon